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2 - N u m e r i c a l   2

Problem

A carbon electrode has a resistance of 0.125 Ω0.125 \, \Omega at 20∘C20^\circ \mathrm{C}. The temperature coefficient of resistance for carbon is −0.0005-0.0005. What will be the resistance of the electrode at 85∘C85^\circ \mathrm{C}?

Data

  • Initial resistance: R0=0.125 ΩR_0 = 0.125 \, \Omega
  • Initial temperature: T1=20∘CT_1 = 20^\circ \mathrm{C}
  • Final temperature: T2=85∘CT_2 = 85^\circ \mathrm{C}
  • Temperature coefficient: α=−0.0005\alpha = -0.0005

Prerequisite Concept

  • Temperature-Dependent Resistance:
    RT=R0(1+αΔT), ΔT=T2−T1R_T = R_0 (1 + \alpha \Delta T), \, \Delta T = T_2 - T_1

Solution

  1. Temperature change:
    ΔT=T2−T1=85−20=65∘C\Delta T = T_2 - T_1 = 85 - 20 = 65^\circ \mathrm{C}

  2. Resistance at T2T_2:
    RT=0.125(1+(−0.0005)(65))R_T = 0.125 (1 + (-0.0005)(65))
    RT=0.125(1−0.0325)=0.125⋅0.9675=0.12 ΩR_T = 0.125 (1 - 0.0325) = 0.125 \cdot 0.9675 = 0.12 \, \Omega

Answer

  • Resistance at 85∘C85^\circ \mathrm{C}: RT=0.12 ΩR_T = 0.12 \, \Omega