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2 - N u m e r i c a l   5

Problem

A 10 W10 \, \mathrm{W} resistor has a value of 120 Ω120 \, \Omega. What is the rated current through the resistor?

Data

  • Power: P=10 WP = 10 \, \mathrm{W}
  • Resistance: R=120 ΩR = 120 \, \Omega

Prerequisite Concept

  • Power Formula:
    P=I2R  ⟹  I=PRP = I^2 R \implies I = \sqrt{\frac{P}{R}}

Solution

Substitute the values:

I=10120=0.0833=0.2886 A.I = \sqrt{\frac{10}{120}} = \sqrt{0.0833} = 0.2886 \, \mathrm{A}.

Answer

  • Rated Current: I=0.2886 AI = 0.2886 \, \mathrm{A}