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5 - N u m e r i c a l   2

Problem

The RMS value of current in an AC circuit is 10 A10 \, \mathrm{A}. What is the peak current?

Data

  • RMS current: Irms=10 AI_{\text{rms}} = 10 \, \mathrm{A}
  • To find: Peak current ImaxI_{\text{max}}

Prerequisite Concepts

The RMS current (IrmsI_{\text{rms}}) is related to the peak current (ImaxI_{\text{max}}) by the formula:

Irms=Imax2I_{\text{rms}} = \frac{I_{\text{max}}}{\sqrt{2}}

Rearranging to find ImaxI_{\text{max}}:

Imax=2×IrmsI_{\text{max}} = \sqrt{2} \times I_{\text{rms}}

Solution

Substitute the given values into the formula:

Imax=2×10 AI_{\text{max}} = \sqrt{2} \times 10 \, \mathrm{A} Imax=1.41×10 AI_{\text{max}} = 1.41 \times 10 \, \mathrm{A} Imax=14.1 AI_{\text{max}} = 14.1 \, \mathrm{A}

Answer

The peak current is 14.1 A14.1 \, \mathrm{A}.