Problem
(a) Calculate the inductive reactance of a 3.00mH inductor when 60.0Hz and 10.0kHz AC voltage are applied.
(b) Determine the rms current at each frequency if the applied rms voltage is 120V.
Data
- Inductance: L=3.00mH=3.00Γ10β3H
- AC frequency 1: f1β=60.0Hz
- AC frequency 2: f2β=10.0kHz=10Γ103Hz
- RMS voltage: Vrmsβ=120V
Prerequisite Concepts
- Inductive reactance is given by:
XLβ=2ΟfL
- RMS current is related to inductive reactance by Ohmβs law:
Irmsβ=XLβVrmsββ
Solution
Part (a): Calculate Inductive Reactance at Each Frequency
For f1β=60.0Hz:
XL1β=2Οf1βL
Substitute the values:
XL1β=2Γ3.14Γ60.0HzΓ3.00Γ10β3H
XL1β=1.1304Ξ©
For f2β=10.0kHz:
XL2β=2Οf2βL
Substitute the values:
XL2β=2Γ3.14Γ10Γ103HzΓ3.00Γ10β3H
XL2β=188.4Ξ©
Part (b): Calculate RMS Current at Each Frequency
For f1β=60.0Hz:
Irms1β=XL1βVrmsββ
Substitute the values:
Irms1β=1.1304Ξ©120Vβ
Irms1β=106.16A
For f2β=10.0kHz:
Irms2β=XL2βVrmsββ
Substitute the values:
Irms2β=188.4Ξ©120Vβ
Irms2β=0.637A
Answer
- Inductive Reactance:
- At f1β=60.0Hz: XL1β=1.1304Ξ©
- At f2β=10.0kHz: XL2β=188.4Ξ©
- RMS Current:
- At f1β=60.0Hz: Irms1β=106.16A
- At f2β=10.0kHz: Irms2β=0.637A