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5 - N u m e r i c a l   6

Problem

(a) Calculate the inductive reactance of a 3.00 mH3.00 \, \mathrm{mH} inductor when 60.0 Hz60.0 \, \mathrm{Hz} and 10.0 kHz10.0 \, \mathrm{kHz} AC voltage are applied.
(b) Determine the rms current at each frequency if the applied rms voltage is 120 V120 \, \mathrm{V}.

Data

  • Inductance: L=3.00 mH=3.00Γ—10βˆ’3 HL = 3.00 \, \mathrm{mH} = 3.00 \times 10^{-3} \, \mathrm{H}
  • AC frequency 1: f1=60.0 Hzf_1 = 60.0 \, \mathrm{Hz}
  • AC frequency 2: f2=10.0 kHz=10Γ—103 Hzf_2 = 10.0 \, \mathrm{kHz} = 10 \times 10^{3} \, \mathrm{Hz}
  • RMS voltage: Vrms=120 VV_{\mathrm{rms}} = 120 \, \mathrm{V}

Prerequisite Concepts

  1. Inductive reactance is given by:
XL=2Ο€fL X_L = 2 \pi f L
  1. RMS current is related to inductive reactance by Ohm’s law:
Irms=VrmsXL I_{\mathrm{rms}} = \frac{V_{\mathrm{rms}}}{X_L}

Solution

Part (a): Calculate Inductive Reactance at Each Frequency

For f1=60.0 Hzf_1 = 60.0 \, \mathrm{Hz}:

XL1=2Ο€f1LX_{L1} = 2 \pi f_1 L

Substitute the values:

XL1=2Γ—3.14Γ—60.0 HzΓ—3.00Γ—10βˆ’3 HX_{L1} = 2 \times 3.14 \times 60.0 \, \mathrm{Hz} \times 3.00 \times 10^{-3} \, \mathrm{H} XL1=1.1304 ΩX_{L1} = 1.1304 \, \Omega

For f2=10.0 kHzf_2 = 10.0 \, \mathrm{kHz}:

XL2=2Ο€f2LX_{L2} = 2 \pi f_2 L

Substitute the values:

XL2=2Γ—3.14Γ—10Γ—103 HzΓ—3.00Γ—10βˆ’3 HX_{L2} = 2 \times 3.14 \times 10 \times 10^{3} \, \mathrm{Hz} \times 3.00 \times 10^{-3} \, \mathrm{H} XL2=188.4 ΩX_{L2} = 188.4 \, \Omega

Part (b): Calculate RMS Current at Each Frequency

For f1=60.0 Hzf_1 = 60.0 \, \mathrm{Hz}:

Irms1=VrmsXL1I_{\mathrm{rms}1} = \frac{V_{\mathrm{rms}}}{X_{L1}}

Substitute the values:

Irms1=120 V1.1304 ΩI_{\mathrm{rms}1} = \frac{120 \, \mathrm{V}}{1.1304 \, \Omega} Irms1=106.16 AI_{\mathrm{rms}1} = 106.16 \, \mathrm{A}

For f2=10.0 kHzf_2 = 10.0 \, \mathrm{kHz}:

Irms2=VrmsXL2I_{\mathrm{rms}2} = \frac{V_{\mathrm{rms}}}{X_{L2}}

Substitute the values:

Irms2=120 V188.4 ΩI_{\mathrm{rms}2} = \frac{120 \, \mathrm{V}}{188.4 \, \Omega} Irms2=0.637 AI_{\mathrm{rms}2} = 0.637 \, \mathrm{A}

Answer

  • Inductive Reactance:
    • At f1=60.0 Hzf_1 = 60.0 \, \mathrm{Hz}: XL1=1.1304 ΩX_{L1} = 1.1304 \, \Omega
    • At f2=10.0 kHzf_2 = 10.0 \, \mathrm{kHz}: XL2=188.4 ΩX_{L2} = 188.4 \, \Omega
  • RMS Current:
    • At f1=60.0 Hzf_1 = 60.0 \, \mathrm{Hz}: Irms1=106.16 AI_{\mathrm{rms}1} = 106.16 \, \mathrm{A}
    • At f2=10.0 kHzf_2 = 10.0 \, \mathrm{kHz}: Irms2=0.637 AI_{\mathrm{rms}2} = 0.637 \, \mathrm{A}