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E l e c t r i c   P o t e n t i a l   D i f f e r e n c e

Definition

The electric potential difference between two points is the work done to move a unit positive charge from one point to another while keeping the charge in electrostatic equilibrium.

Explanation

Consider two oppositely charged parallel plates with a unit positive Charge +q0+q_0 placed between them.

Electric Potential Difference

a) Movement from Positive Plate to Negative Plate

  • The charge +q0+q_0 moves freely along the electric field lines toward the negative plate, driven by electric force.
  • During this movement, the charge gains an equivalent amount of kinetic energy.

b) Movement from Negative Plate to Positive Plate

  • To move +q0+q_0 against the direction of the Electric Field, an external force equal and opposite to Fβƒ—=q0Eβƒ—\vec{F} = q_0\vec{E} must be applied.
  • This keeps the charge in electrostatic equilibrium, enabling it to move at a uniform velocity without acceleration.

c) Work Done on the Charge

If:

  • Potential energy at point A=UAA = U_A
  • Potential energy at point B=UBB = U_B
  • Work done to move the charge from BB to A=WBAA = W_{BA}

Then:

UAβˆ’UB=WBAorΞ”U=WBAU_A - U_B = W_{BA} \quad \text{or} \quad \Delta U = W_{BA}

Dividing both sides by q0q_0:

Ξ”Uq0=WBAq0\frac{\Delta U}{q_0} = \frac{W_{BA}}{q_0}

The electric potential difference Ξ”V\Delta V is defined as the work done per unit charge:

Ξ”V=WBAq0\Delta V = \frac{W_{BA}}{q_0}

Physical Significance

  • Determines the direction of flow for positive charges.
  • Positive charges always move from higher potential to lower potential.

Nature and Units

  • Electric potential difference is a scalar quantity.
  • SI unit: volt (V), where:
1 volt=1 joule1 coulomb 1 \, \text{volt} = \frac{1 \, \text{joule}}{1 \, \text{coulomb}}
  • Multiples and submultiples of volt include:
    • 1 mV=10βˆ’3 V1 \, \mathrm{mV} = 10^{-3} \, \mathrm{V}
    • 1 μV=10βˆ’6 V1 \, \mu\mathrm{V} = 10^{-6} \, \mathrm{V}
    • 1 kV=103 V1 \, \mathrm{kV} = 10^{3} \, \mathrm{V}
    • 1 MV=106 V1 \, \mathrm{MV} = 10^{6} \, \mathrm{V}
    • 1 GV=109 V1 \, \mathrm{GV} = 10^{9} \, \mathrm{V}

Electric Potential

a) Definition

Electric potential at a point is the work done in bringing a unit positive charge from infinity to that point without any acceleration.

b) Explanation

From the potential difference formula:

Ξ”V=WBAq0orVAβˆ’VB=WBAq0\Delta V = \frac{W_{BA}}{q_0} \quad \text{or} \quad V_A - V_B = \frac{W_{BA}}{q_0}

If point BB is at infinity:

VB=V∞=0V_B = V_\infty = 0

Then:

VAβˆ’0=W∞Aq0orVA=W∞Aq0V_A - 0 = \frac{W_{\infty A}}{q_0} \quad \text{or} \quad V_A = \frac{W_{\infty A}}{q_0}

Thus, the absolute electric potential at a point is:

V=Wq0V = \frac{W}{q_0}

Where VV is the electric potential, and WW is the work done.


Summary

ConceptDefinitionKey Formula
Electric Potential DifferenceWork done to move a unit positive charge between two points in electrostatic equilibrium.Ξ”V=WBAq0\Delta V = \frac{W_{BA}}{q_0}
Electric PotentialWork done to bring a unit positive charge from infinity to a specific point without acceleration.V=Wq0V = \frac{W}{q_0}
UnitsSI unit is volt (V). Other units include millivolts, kilovolts, etc.1 volt=1 joule1 coulomb1 \, \text{volt} = \frac{1 \, \text{joule}}{1 \, \text{coulomb}}

Significance

Understanding electric potential and potential difference is essential in analyzing electric circuits, fields, and energy transformations, enabling practical applications like batteries, capacitors, and electric power systems.


References