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Electric Potential Energy

Definition

Electric potential energy at a point is the work done against the electric field when a unit positive Charge is brought from infinity to that point. The unit charge is moved without accelerating.

Explanation

Consider an isolated charge QQ fixed in space. A test charge qq is initially at infinity and is moved towards the charge +Q+Q. Due to the repulsive force between the two charges, external work must be done to move the test charge from infinity to a point near the charge QQ.

  • External work is required to bring the charge from infinity to point B due to the repulsion between the charges. This results in a negative work value.
  • Let the test charge be at a large distance rAr_A from charge QQ. The distance between rAr_A and rBr_B is divided into infinitesimally small displacements r1,r2,,rNr_1, r_2, \dots, r_N, ensuring that the field intensity remains constant over each displacement.

Electric Potential Energy Diagram

Work from rAr_A to r1r_1

The test charge is moved from rAr_A to r1r_1 with a small displacement Δr\Delta r. Since external work is done to move the charge against the electric field, we include a negative sign in the equation.

ΔWrAr1=FΔrcosθ\Delta W_{r_A \rightarrow r_1} = -F \Delta r \cos \theta

Substitute the expression for force F=14πε0Qqr2F = \frac{1}{4 \pi \varepsilon_0} \frac{Qq}{r^2}:

ΔWrAr1=14πε0Qqr2Δrcosθ\Delta W_{r_A \rightarrow r_1} = -\frac{1}{4 \pi \varepsilon_0} \frac{Qq}{r^2} \Delta r \cos \theta

Since θ=180\theta = 180^\circ (because the test charge is moved against the electric field), we have:

ΔWrAr1=Qq4πε01r2Δr\Delta W_{r_A \rightarrow r_1} = \frac{Q q}{4 \pi \varepsilon_0} \frac{1}{r^2} \Delta r

Rewriting in terms of rAr_A and r1r_1:

ΔWrAr1=Qq4πε0(1rA1r1)\Delta W_{r_A \rightarrow r_1} = \frac{Qq}{4 \pi \varepsilon_0} \left( \frac{1}{r_A} - \frac{1}{r_1} \right)

Work from r1r_1 to r2r_2

Similarly, the work done in moving the test charge from r1r_1 to r2r_2 is given by:

ΔWr1r2=Qq4πε0(1r21r1)\Delta W_{r_1 \rightarrow r_2} = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r_2} - \frac{1}{r_1} \right)

Work from rNr_N to rBr_B

For the final displacement, the work done to move the charge from rNr_N to rBr_B is:

ΔWrNrB=Qq4πε0(1rB1rN)\Delta W_{r_N \rightarrow r_B} = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r_B} - \frac{1}{r_N} \right)

Total Work from rAr_A to rBr_B

The total work done from rAr_A to rBr_B can be written as the sum of all the infinitesimal works:

ΔWrArB=Qq4πε0(1r11rA+1r21r1++1rB1rN)\Delta W_{r_A \rightarrow r_B} = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r_1} - \frac{1}{r_A} + \frac{1}{r_2} - \frac{1}{r_1} + \dots + \frac{1}{r_B} - \frac{1}{r_N} \right)

Simplifying the series, we get:

ΔWrArB=Qq4πε0(1rB1rA)\Delta W_{r_A \rightarrow r_B} = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r_B} - \frac{1}{r_A} \right)

The work done to move a test charge qq from infinity to a distance rr from QQ is:

ΔWrArB=Qq4πε0(1rB0)=Qq4πε0(1rB)\Delta W_{r_A \rightarrow r_B} = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r_B} - 0 \right) = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r_B} \right)

Thus, the work done is given by:

ΔW=Qq4πε0(1r)\Delta W = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r} \right)

Therefore, the electric potential energy UU is:

U=Qq4πε0(1r)U = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r} \right)

Electric Potential

The electric potential at a distance rr from QQ is defined as:

V=WqV = \frac{W}{q}

Substituting W=Qq4πε0(1r)W = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r} \right):

V=Qq4πε0(1r)qV = \frac{\frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r} \right)}{q}

Simplifying:

V=Q4πε0(1r)V = \frac{Q}{4 \pi \varepsilon_0} \left( \frac{1}{r} \right)

Thus, the electric potential is:

V=14πε0QrV = \frac{1}{4 \pi \varepsilon_0} \frac{Q}{r}

Summary

  1. Electric Potential Energy: The work done to move a test Charge from infinity to a point near a charge QQ in an Electric Field.

  2. Electric Potential: The potential energy per unit charge at a point in the field.

Important Relationships:

  1. Work Done: ΔW=Qq4πε0(1r)\Delta W = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r} \right)
  2. Electric Potential: V=14πε0QrV = \frac{1}{4 \pi \varepsilon_0} \frac{Q}{r}
ConceptFormulaDescription
Electric Potential EnergyU=Qq4πε0(1r)U = \frac{Q q}{4 \pi \varepsilon_0} \left( \frac{1}{r} \right)Work done to move a test charge in an electric field.
Electric PotentialV=14πε0QrV = \frac{1}{4 \pi \varepsilon_0} \frac{Q}{r}The potential energy per unit charge at a point in the field.

Electric potential energy and potential are crucial concepts in understanding how charges interact within electric fields. These principles have broad applications in areas such as electrostatics, capacitors, and more.

References

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